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Specific Gravity Practice Problems

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Specific gravity relates a liquid's weight to its volume, so you can convert between grams and milliliters. You need it whenever a formula is written by weight but the ingredient is measured by volume, or the other way round.

Formulaspecific gravity = weight (g) ÷ volume (mL), a unitless number because it compares to water at 1 g/mL  →  weight = volume × SG  •  volume = weight ÷ SG
Worked example

Glycerin has a specific gravity of 1.25. The weight of 240 mL = 240 × 1.25 = 300 g.

Numerically, SG equals grams per mL because it's referenced to water (1 g/mL).


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Specific Gravity
PEG 400 has a specific gravity of 1.13. What is the weight in grams of 855 mL? Round your answer to one decimal place.
g

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How to use specific gravity

Specific gravity is the weight of a liquid compared with the weight of the same volume of water. Water weighs 1 g per mL, so a liquid's specific gravity is numerically its grams per millilitre, and that's the whole use of it: it converts between a volume and a weight. Formulas are often written by weight while the ingredients are measured by volume, or the reverse, and specific gravity is the bridge.

weight (g) = volume (mL) × SG   •   volume (mL) = weight (g) ÷ SG   •   SG = weight (g) ÷ volume (mL)

Specific gravity has no unit, because it's a ratio of two weights. Treat it as g/mL in the arithmetic anyway; the units come out right.

Worked example 1: volume to weight

Glycerin has a specific gravity of 1.25. What does 120 mL weigh?

weight = 120 × 1.25 = 150 g

Worked example 2: weight to volume

Alcohol has a specific gravity of 0.81. What volume contains 100 g?

volume = 100 ÷ 0.81 = 123.46 → 123.5 mL

A liquid lighter than water takes up more than 100 mL per 100 g; a liquid heavier than water takes up less. That's the sanity check. Glycerin at 1.25 makes 100 g fit into 80 mL. Alcohol at 0.81 needs 123.5 mL for the same weight. If your answer moves in the wrong direction, you multiplied where you should have divided.

Worked example 3: finding the specific gravity

60 mL of a syrup weighs 78 g.

SG = 78 ÷ 60 = 1.3

A question may give this as a pycnometer or a graduated-cylinder measurement: the empty container weighs so much, the container plus liquid weighs so much more, and the volume is known. Subtract the container's weight before dividing.

Where it shows up inside other problems

A percent w/w formula that has to be made to a volume. A compounding order listing an ingredient in grams that the pharmacy stocks and measures as a liquid. A w/v strength of a liquid-in-liquid preparation. In each case the specific gravity step comes first, so that everything is in one kind of unit before the main calculation. When a question mentions specific gravity and you can't see why, look for the place where a weight and a volume are about to be compared.

Where students lose the points

10 Specific Gravity practice problems with worked solutions

Every problem below is worked start to finish. Try it yourself first, then check the steps. For a fresh problem every time, use the practice box above. It generates unlimited variations of these same question types.

Problem 1: Specific Gravity

A syrup has a specific gravity of 1.31. What is the weight in grams of 835 mL? Round your answer to one decimal place.

Answer 1,093.9 g

Solution
  1. weight (g) = volume (mL) × specific gravity (g/mL).
  2. weight = 835 mL × 1.31 g/mL = 1093.85 g.
  3. Rounded as the question asks: 1,093.9 g.

Specific gravity = weight of a substance ÷ weight of an equal volume of water; numerically it's grams per mL.

Problem 2: Specific Gravity

Alcohol has a specific gravity of 0.81. What volume in mL contains 15 g? Round your answer to one decimal place.

Answer 18.5 mL

Solution
  1. volume (mL) = weight (g) ÷ specific gravity (g/mL).
  2. volume = 15 g ÷ 0.81 g/mL ≈ 18.519 mL.
  3. Rounded as the question asks: 18.5 mL.

Rearranged from weight = volume × specific gravity. A liquid denser than water (SG > 1) occupies less volume per gram.

Problem 3: Specific Gravity

Mineral oil has a specific gravity of 0.87. What volume in mL contains 500 g? Round your answer to one decimal place.

Answer 574.7 mL

Solution
  1. volume (mL) = weight (g) ÷ specific gravity (g/mL).
  2. volume = 500 g ÷ 0.87 g/mL ≈ 574.713 mL.
  3. Rounded as the question asks: 574.7 mL.

Rearranged from weight = volume × specific gravity. A liquid denser than water (SG > 1) occupies less volume per gram.

Problem 4: Specific Gravity

Castor oil has a specific gravity of 0.96. What is the weight in grams of 30 mL? Round your answer to one decimal place.

Answer 28.8 g

Solution
  1. weight (g) = volume (mL) × specific gravity (g/mL).
  2. weight = 30 mL × 0.96 g/mL = 28.8 g.
  3. Rounded as the question asks: 28.8 g.

Specific gravity = weight of a substance ÷ weight of an equal volume of water; numerically it's grams per mL.

Problem 5: Specific Gravity

Glycerin has a specific gravity of 1.25. What is the weight in grams of 705 mL? Round your answer to one decimal place.

Answer 881.3 g

Solution
  1. weight (g) = volume (mL) × specific gravity (g/mL).
  2. weight = 705 mL × 1.25 g/mL = 881.25 g.
  3. Rounded as the question asks: 881.3 g.

Specific gravity = weight of a substance ÷ weight of an equal volume of water; numerically it's grams per mL.

Problem 6: Specific Gravity

A syrup has a specific gravity of 1.31. What volume in mL contains 260 g? Round your answer to one decimal place.

Answer 198.5 mL

Solution
  1. volume (mL) = weight (g) ÷ specific gravity (g/mL).
  2. volume = 260 g ÷ 1.31 g/mL ≈ 198.473 mL.
  3. Rounded as the question asks: 198.5 mL.

Rearranged from weight = volume × specific gravity. A liquid denser than water (SG > 1) occupies less volume per gram.

Problem 7: Specific Gravity

Mineral oil has a specific gravity of 0.87. What is the weight in grams of 840 mL? Round your answer to one decimal place.

Answer 730.8 g

Solution
  1. weight (g) = volume (mL) × specific gravity (g/mL).
  2. weight = 840 mL × 0.87 g/mL = 730.8 g.
  3. Rounded as the question asks: 730.8 g.

Specific gravity = weight of a substance ÷ weight of an equal volume of water; numerically it's grams per mL.

Problem 8: Specific Gravity

Propylene glycol has a specific gravity of 1.04. What volume in mL contains 405 g? Round your answer to one decimal place.

Answer 389.4 mL

Solution
  1. volume (mL) = weight (g) ÷ specific gravity (g/mL).
  2. volume = 405 g ÷ 1.04 g/mL ≈ 389.423 mL.
  3. Rounded as the question asks: 389.4 mL.

Rearranged from weight = volume × specific gravity. A liquid denser than water (SG > 1) occupies less volume per gram.

Problem 9: Specific Gravity

Propylene glycol has a specific gravity of 1.04. What is the weight in grams of 275 mL? Round your answer to one decimal place.

Answer 286.0 g

Solution
  1. weight (g) = volume (mL) × specific gravity (g/mL).
  2. weight = 275 mL × 1.04 g/mL = 286 g.
  3. Rounded as the question asks: 286.0 g.

Specific gravity = weight of a substance ÷ weight of an equal volume of water; numerically it's grams per mL.

Problem 10: Specific Gravity

Alcohol has a specific gravity of 0.81. What is the weight in grams of 210 mL? Round your answer to one decimal place.

Answer 170.1 g

Solution
  1. weight (g) = volume (mL) × specific gravity (g/mL).
  2. weight = 210 mL × 0.81 g/mL = 170.1 g.
  3. Rounded as the question asks: 170.1 g.

Specific gravity = weight of a substance ÷ weight of an equal volume of water; numerically it's grams per mL.


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